New upstream version 2.3.4

This commit is contained in:
Jan Wagner 2023-10-18 07:29:37 +00:00
parent e7bdd1c6c6
commit de72f6f588
556 changed files with 90432 additions and 53391 deletions

View file

@ -1,19 +1,19 @@
/* Safe automatic memory allocation.
Copyright (C) 2003, 2006-2007, 2009-2013 Free Software Foundation, Inc.
Written by Bruno Haible <bruno@clisp.org>, 2003.
Copyright (C) 2003, 2006-2007, 2009-2023 Free Software Foundation, Inc.
Written by Bruno Haible <bruno@clisp.org>, 2003, 2018.
This program is free software; you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; either version 3, or (at your option)
any later version.
This file is free software: you can redistribute it and/or modify
it under the terms of the GNU Lesser General Public License as
published by the Free Software Foundation; either version 2.1 of the
License, or (at your option) any later version.
This program is distributed in the hope that it will be useful,
This file is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
GNU Lesser General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program; if not, see <http://www.gnu.org/licenses/>. */
You should have received a copy of the GNU Lesser General Public License
along with this program. If not, see <https://www.gnu.org/licenses/>. */
#define _GL_USE_STDLIB_ALLOC 1
#include <config.h>
@ -21,82 +21,56 @@
/* Specification. */
#include "malloca.h"
#include <stdint.h>
#include <stdckdint.h>
#include "verify.h"
#include "idx.h"
/* The speed critical point in this file is freea() applied to an alloca()
result: it must be fast, to match the speed of alloca(). The speed of
mmalloca() and freea() in the other case are not critical, because they
are only invoked for big memory sizes. */
are only invoked for big memory sizes.
Here we use a bit in the address as an indicator, an idea by Ondřej Bílka.
malloca() can return three types of pointers:
- Pointers 0 mod 2*sa_alignment_max come from stack allocation.
- Pointers sa_alignment_max mod 2*sa_alignment_max come from heap
allocation.
- NULL comes from a failed heap allocation. */
#if HAVE_ALLOCA
/* Store the mmalloca() results in a hash table. This is needed to reliably
distinguish a mmalloca() result and an alloca() result.
Although it is possible that the same pointer is returned by alloca() and
by mmalloca() at different times in the same application, it does not lead
to a bug in freea(), because:
- Before a pointer returned by alloca() can point into malloc()ed memory,
the function must return, and once this has happened the programmer must
not call freea() on it anyway.
- Before a pointer returned by mmalloca() can point into the stack, it
must be freed. The only function that can free it is freea(), and
when freea() frees it, it also removes it from the hash table. */
#define MAGIC_NUMBER 0x1415fb4a
#define MAGIC_SIZE sizeof (int)
/* This is how the header info would look like without any alignment
considerations. */
struct preliminary_header { void *next; int magic; };
/* But the header's size must be a multiple of sa_alignment_max. */
#define HEADER_SIZE \
(((sizeof (struct preliminary_header) + sa_alignment_max - 1) / sa_alignment_max) * sa_alignment_max)
union header {
void *next;
struct {
char room[HEADER_SIZE - MAGIC_SIZE];
int word;
} magic;
};
verify (HEADER_SIZE == sizeof (union header));
/* We make the hash table quite big, so that during lookups the probability
of empty hash buckets is quite high. There is no need to make the hash
table resizable, because when the hash table gets filled so much that the
lookup becomes slow, it means that the application has memory leaks. */
#define HASH_TABLE_SIZE 257
static void * mmalloca_results[HASH_TABLE_SIZE];
#endif
/* Type for holding very small pointer differences. */
typedef unsigned char small_t;
/* Verify that it is wide enough. */
static_assert (2 * sa_alignment_max - 1 <= (small_t) -1);
void *
mmalloca (size_t n)
{
#if HAVE_ALLOCA
/* Allocate one more word, that serves as an indicator for malloc()ed
memory, so that freea() of an alloca() result is fast. */
size_t nplus = n + HEADER_SIZE;
if (nplus >= n)
/* Allocate one more word, used to determine the address to pass to freea(),
and room for the alignment sa_alignment_max mod 2*sa_alignment_max. */
uintptr_t alignment2_mask = 2 * sa_alignment_max - 1;
int plus = sizeof (small_t) + alignment2_mask;
idx_t nplus;
if (!ckd_add (&nplus, n, plus) && !xalloc_oversized (nplus, 1))
{
void *p = malloc (nplus);
char *mem = (char *) malloc (nplus);
if (p != NULL)
if (mem != NULL)
{
size_t slot;
union header *h = p;
p = h + 1;
/* Put a magic number into the indicator word. */
h->magic.word = MAGIC_NUMBER;
/* Enter p into the hash table. */
slot = (uintptr_t) p % HASH_TABLE_SIZE;
h->next = mmalloca_results[slot];
mmalloca_results[slot] = p;
uintptr_t umem = (uintptr_t)mem, umemplus;
/* The ckd_add avoids signed integer overflow on
theoretical platforms where UINTPTR_MAX <= INT_MAX. */
ckd_add (&umemplus, umem, sizeof (small_t) + sa_alignment_max - 1);
idx_t offset = ((umemplus & ~alignment2_mask)
+ sa_alignment_max - umem);
void *vp = mem + offset;
small_t *p = vp;
/* Here p >= mem + sizeof (small_t),
and p <= mem + sizeof (small_t) + 2 * sa_alignment_max - 1
hence p + n <= mem + nplus.
So, the memory range [p, p+n) lies in the allocated memory range
[mem, mem + nplus). */
p[-1] = offset;
/* p ≡ sa_alignment_max mod 2*sa_alignment_max. */
return p;
}
}
@ -115,35 +89,24 @@ mmalloca (size_t n)
void
freea (void *p)
{
/* mmalloca() may have returned NULL. */
if (p != NULL)
/* Check argument. */
if ((uintptr_t) p & (sa_alignment_max - 1))
{
/* Attempt to quickly distinguish the mmalloca() result - which has
a magic indicator word - and the alloca() result - which has an
uninitialized indicator word. It is for this test that sa_increment
additional bytes are allocated in the alloca() case. */
if (((int *) p)[-1] == MAGIC_NUMBER)
{
/* Looks like a mmalloca() result. To see whether it really is one,
perform a lookup in the hash table. */
size_t slot = (uintptr_t) p % HASH_TABLE_SIZE;
void **chain = &mmalloca_results[slot];
for (; *chain != NULL;)
{
union header *h = p;
if (*chain == p)
{
/* Found it. Remove it from the hash table and free it. */
union header *p_begin = h - 1;
*chain = p_begin->next;
free (p_begin);
return;
}
h = *chain;
chain = &h[-1].next;
}
}
/* At this point, we know it was not a mmalloca() result. */
/* p was not the result of a malloca() call. Invalid argument. */
abort ();
}
/* Determine whether p was a non-NULL pointer returned by mmalloca(). */
if ((uintptr_t) p & sa_alignment_max)
{
void *mem = (char *) p - ((small_t *) p)[-1];
free (mem);
}
}
#endif
/*
* Hey Emacs!
* Local Variables:
* coding: utf-8
* End:
*/